(a) u × v = (-4 + 4)i - (4 + 4)j + (4 + 4)k

= 0 i - 8j + 8k

(b) v × u = (-4 + 4)i - (-4 - 4)j + (-4 - 4) k

= 0i + 8i - 8k

(c) v × v = (16 - 16)i - (16 - 16)j + (16 - 16)k

= 0i - 0j + 0k

= 0

Not sure what is stopping you from using the formula.

The x component of u x v is (uy*vz - vy*uz) = (-1)*4 - 4*(-1). Just plug in the numbers.

And do the same for (u x v)_y = (uz*vx - vz*ux) and (u x v)_z = (ux*vy - vx*uy). Just plug in.

v x u is the negative of u x v. True for any two vectors.

v x v is 0. True for any vector.