d(u, v) =
d² = 4² + (-4)² = 32
d = 4 √2 cm
Distance between (x1,y1) and (x2,y2) is:
SQRT{(x2-x1)^2+(y2-y1)^2]
Coordinates (-2,2) and (2,-2)
Distance = SQRT[(-2-2)^2)+(2+2)^2]
= sqrt[16+16]
= sqrt[32]
= sqrt(16)sqrt(2)
= 4 sqrt(2)
Distance = 5.656854
d(u,v)=√((ux-vx)²+(uy-vy)²)=
=√((-4)²+(4)²)=√32=4√2
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Answers & Comments
d² = 4² + (-4)² = 32
d = 4 √2 cm
Distance between (x1,y1) and (x2,y2) is:
SQRT{(x2-x1)^2+(y2-y1)^2]
Coordinates (-2,2) and (2,-2)
Distance = SQRT[(-2-2)^2)+(2+2)^2]
= sqrt[16+16]
= sqrt[32]
= sqrt(16)sqrt(2)
= 4 sqrt(2)
Distance = 5.656854
d(u,v)=√((ux-vx)²+(uy-vy)²)=
=√((-4)²+(4)²)=√32=4√2