What mass of CH4 is contained in a 500.-mL sample of CH4 at - 40.0°C and 300. torr? Answer 0.0870 g 0.16?
Update:
The answer is .165 g
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The answer is .165 g
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PV = nRT
n = PV / RT = (300 torr) x (0.500 L) / ((62.36367 L Torr/K mol) x (40.0 + 273.15 K)) =
0.0076808 mol
(0.0076808 mol) x (16.04257 g CH4/mol) = 0.123 g CH4