Consider the following reaction: N2(g) + 3 H2(g) −→ 2 NH3(g)?
If this reaction is carried out under standard conditions, estimate the work for the
system per mole of reaction.
1. −5 kJ·mol−1
2. −10 kJ·mol−1
3. 10 J·mol−1
4. 10 kJ·mol−1
5. 5 kJ·mol−1
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N2(g) + 3 H2(g) −→ 2 NH3(g)
If delta V is change in volume that takes place during the reaction, P*deltaV is the work done by gas
when it expands
P*deltaV= delta n RT ( T is not given, assumed = 298 k)
delta n = increase in no of moles of gas = -2
Work done = -2*8.31451*298 = - 4.955 kj / mol ( ties up with 1)
R = 8.31451j / mol k