Find the probability of a 4 turning up at once in two tosses of a fair die. Let A1 = event “4 on first toss an?
Find the probability of a 4 turning up at once in two tosses of a fair die. Let A1 = event “4 on first toss and A2 = event “4 on second toss.thenA1 or A2 = event “4 on first toss or 4 on second toss or both = event “at least one 4 turns up “
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The probability of A1 or A2 = the probability of A1 + the probability of A2
P(A1) = 1/6
P(A2) = 1/6
P(A1 or A2) = 1/6 + 1/6 = 2/6 = 1/3
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If you think about it, there are 36 possible outcomes (6 options first roll x 6 options second roll)
How many have at least one 4?
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6) (1,4) (2,4) (3,4) (4,4) (5,4) (6,4)
12 / 36 = 1 / 3