f '(x) = [(2x - 9)(2x - 3) - 2(x² - 3x + 1)]/(2x - 9)²
well its just a simple quotient rule if that helps
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f '(x) = [(2x - 9)(2x - 3) - 2(x² - 3x + 1)]/(2x - 9)²
well its just a simple quotient rule if that helps