subtract 6 from the right side to make x²-5x-6 = 0.
now factor: (x+1)(x-6) = 0.
x+1= 0 or x-6 = 0 (because when the product of 2 numbers is 0 , at least one of the numbers has to be 0)
so x = -1 or x = 6
and the solution set is {-1, 6}
:]
1) To find x-intercepts, why has to equal 0:
x^2 - 5x - 6 = 0
2) Factor the quadratic:
(x - 6)(x + 1) = 0
3) Set each factor equal to 0 and solve:
x - 6 = 0
x = 6
or
x + 1 = 0
x = - 1
you can factorize
so if x = 6, the first factor is 0, and if x = -1, the second factor is 0.
So they're the two possible answers.
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subtract 6 from the right side to make x²-5x-6 = 0.
now factor: (x+1)(x-6) = 0.
x+1= 0 or x-6 = 0 (because when the product of 2 numbers is 0 , at least one of the numbers has to be 0)
so x = -1 or x = 6
and the solution set is {-1, 6}
:]
1) To find x-intercepts, why has to equal 0:
x^2 - 5x - 6 = 0
2) Factor the quadratic:
(x - 6)(x + 1) = 0
3) Set each factor equal to 0 and solve:
x - 6 = 0
x = 6
or
x + 1 = 0
x = - 1
x^2 - 5x - 6 = 0
you can factorize
(x - 6)(x + 1) = 0
so if x = 6, the first factor is 0, and if x = -1, the second factor is 0.
So they're the two possible answers.