Suppose that P(A) = 0.3 and P(B) = 0.3 and P(A ∩ B) = 0.1.
Find each of the following conditional probabilities
P(B | Ac) =
P(Ac) = 1 - P(A) = 1 - 0.3 = 0.7
P(Ac ∩ B) = P(B) - P(A ∩ B) = 0.3 - 0.1 = 0.2
P(B | Ac) = P(Ac ∩ B) / P(Ac) = 0.2/0.7 = 2/7
= about 0.286
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Answers & Comments
P(Ac) = 1 - P(A) = 1 - 0.3 = 0.7
P(Ac ∩ B) = P(B) - P(A ∩ B) = 0.3 - 0.1 = 0.2
P(B | Ac) = P(Ac ∩ B) / P(Ac) = 0.2/0.7 = 2/7
= about 0.286