Verified answer

If an ice-cream cone has a height of 6 in and a diameter of 3 in,

how much ice cream can the cone hold?

V = 1/3(2 1/4) 6 pi in^3 = 14.137166941154069 in^3

V = 14.1 (the nearest tenth) in^3.

An ice-cream cone has a height of 6 in and a diameter of 3 in, 

how much ice cream can the cone hold?

V = 1/3(2 1/4) 6 pi in^3 = 14.137166941154069 in^3

V = 14.1 (the nearest tenth) in^3.

volume =

1/3 * pi r^2 h =

1/3 * pi(3/2)^2 * 6 =

9pi/2 in^3

Given

r = 3/2 = 1.5 in

V = 1/3πr^2h

V = 1/3π(1.5)^2(6)

V = 14.1 in^3 Answer//

The equation for the volume of a cone is:

V = πr²h / 3

You are given a diameter of 3, which is a radius of (3/2).  Substitute that along with h = 6 and simplify:

V = π(3/2)²(6) / 3

V = π(9/4)(2)

V = (9/2)π in³