Note that: cos(1/3 π) = 1/2
c² = a² + b² − 2ab ∙ cos(γ) =
16² + 8² − 2 ∙ 16 ∙ 8 cos(1/3 π) =
256 + 64 − 256 cos(1/3 π) =
320 − 256 cos(1/3 π) =
320 − 256 ∙ 1/2 =
320 − 128 =
192
But this is c² ! Therefore:
c = √(c²) = √192 = √64 ∙ √3 = 8√3
You don't ... cos(π/3) = 1/2, so just multiply all these terms together.
256 + 64 – 128 = 192
Unless I'm missing something in your notation ....
Hope that helps!
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Note that: cos(1/3 π) = 1/2
c² = a² + b² − 2ab ∙ cos(γ) =
16² + 8² − 2 ∙ 16 ∙ 8 cos(1/3 π) =
256 + 64 − 256 cos(1/3 π) =
320 − 256 cos(1/3 π) =
320 − 256 ∙ 1/2 =
320 − 128 =
192
But this is c² ! Therefore:
c = √(c²) = √192 = √64 ∙ √3 = 8√3
You don't ... cos(π/3) = 1/2, so just multiply all these terms together.
256 + 64 – 128 = 192
Unless I'm missing something in your notation ....
Hope that helps!