find f^-1(x) when f(x) = 3√ x-3 Solve?
Find f^-1(x).
f(x) = 3√ x-3 <<<(the first 3 in this section is the small three that goes in the little crease, but still outside the square root. I don't know how to express that without writing it out.)
f^-1(x)=
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Recall that f(f^-1) = x.
f(x) = (x - 3)^(1/3)
(f^-1 - 3)^(1/3) = x
f^-1 - 3 = x^3
f^-1 = x^3 + 3