It seems so simple but I don't get it:( I keep getting x = a/b but that's not an option for the answers.
x + bx/c = a
x + bx = ac
x(1 + b) = ac
x = ac / (b + 1)
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The first answerer incorrectly multiplied both sides by c in the first step, due to not multiplying the x term by c.
Here are two correct methods.
Method 1:
c(x + bx/c) = ac
cx + bx = ac
x(b + c) = ac
x = ac/(b + c).
Method 2:
x(1 + b/c) = a
x = a/(1 + b/c) = ac/[c(1 + b/c)] = ac/(c + b) = ac/(b + c).
In either case, x = ac/(b + c).
Lord bless you today!
X Bx
xc + bx = ac (multiply all terms by c)
x(b+c) = ac
x=ac/(b+c) [note: we can divide both sides by (b+c) since (b+c) is NOT equal to zero.]
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Verified answer
x + bx/c = a
x + bx = ac
x(1 + b) = ac
x = ac / (b + 1)
¯¯¯¯¯¯¯¯¯¯¯¯¯
The first answerer incorrectly multiplied both sides by c in the first step, due to not multiplying the x term by c.
Here are two correct methods.
Method 1:
x + bx/c = a
c(x + bx/c) = ac
cx + bx = ac
x(b + c) = ac
x = ac/(b + c).
Method 2:
x + bx/c = a
x(1 + b/c) = a
x = a/(1 + b/c) = ac/[c(1 + b/c)] = ac/(c + b) = ac/(b + c).
In either case, x = ac/(b + c).
Lord bless you today!
X Bx
x + bx/c = a
xc + bx = ac (multiply all terms by c)
x(b+c) = ac
x=ac/(b+c) [note: we can divide both sides by (b+c) since (b+c) is NOT equal to zero.]
¯¯¯¯¯¯¯¯¯