If y=f(u)=10cos(6u) and u=g(x)=e^4x
What would dy/dx be?
dy/du = -10sin(6u) * 6 du/dx = -60sin(6u) du/dx
du/dx = 4e^(4x)...assuming e^4x should be e^(4x)
dy/dx = dy/du * du/dx = -60sin(6u) * 4e^(4x) =
-240sin(6u) e^(4x) =
-240sin(6e^4x) e^(4x)
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Answers & Comments
dy/du = -10sin(6u) * 6 du/dx = -60sin(6u) du/dx
du/dx = 4e^(4x)...assuming e^4x should be e^(4x)
dy/dx = dy/du * du/dx = -60sin(6u) * 4e^(4x) =
-240sin(6u) e^(4x) =
-240sin(6e^4x) e^(4x)