Solve for c. a(c−b)=d
(c−b) = d/a
c = d/a + b
a(c − b) = d
ac - ab = d
ac = ab + d
c = b + d/a
The solution is: c = d/a +b
If a is zero and d is zero, c can be any number.
If a is zero and d isn't zero, there is no valid number that c can be.
If a isn't zero then you can divide both sides by a
c-b = d/a
then add b
c = d/a + b for a not equal to zero
a(c - b) = d
c - b = d/a
-
c = b + ( d / a )...............divide both sides by a , then add b to both sides
c = b + (d/a)
ac-ab=d
ac=d+ab
C=(d+ab)/a
We have ac - ab = d; so that c = (d + ab)/a ANS.
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Answers & Comments
Solve for c. a(c−b)=d
(c−b) = d/a
c = d/a + b
a(c − b) = d
ac - ab = d
ac = ab + d
c = b + d/a
The solution is: c = d/a +b
If a is zero and d is zero, c can be any number.
If a is zero and d isn't zero, there is no valid number that c can be.
If a isn't zero then you can divide both sides by a
c-b = d/a
then add b
c = d/a + b for a not equal to zero
a(c - b) = d
c - b = d/a
c = d/a + b
-
c - b = d/a
c = d/a + b
c = b + ( d / a )...............divide both sides by a , then add b to both sides
a(c − b) = d
c - b = d/a
c = b + (d/a)
ac-ab=d
ac=d+ab
C=(d+ab)/a
We have ac - ab = d; so that c = (d + ab)/a ANS.