Verified answer

Well you first want to balance the equation:

Fe2O3(s) + 3CO(g) = 2Fe(s) + 3CO2(g)

so you have 3.3 Kg Fe2O3 = 3300 g Fe2O3

Molar mass of Fe2O3 = 159.69 g/mol

To find moles of Fe2O3: 3300/159.69 = 20.665 mol Fe2O3

For every mole of Fe2O3 you need 3 moles of CO. You have 20.665 moles of Fe2O3 so you'll need 20.665*3 = 61.995 moles of CO.

Molar mass of CO = 28 g/mol

To find grams of CO: 61.995*28 = 1735 g CO = 1.735 Kg CO

Sigfigs: 1.7 Kg CO