If the pH of the solution is 4.7, calculate the molar concentration of OH−(aq) in the solution.
Express your answer using one significant figure.
Please explain why as well please!
Thanks! :)
[H+] = 10 ^-pH = 10 ^-4.7 = 2.00 x 10 ^05
[OH]- = 10 ^-14 / [H+} = 10^-14 / 2.00 x 10 ^05
[OH-] = 5 x 10 ^-10 moles / liter
pOH = 9,3
[OH-] = 10^-9,3 M = 5,01*10^-10 M
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[H+] = 10 ^-pH = 10 ^-4.7 = 2.00 x 10 ^05
[OH]- = 10 ^-14 / [H+} = 10^-14 / 2.00 x 10 ^05
[OH-] = 5 x 10 ^-10 moles / liter
pOH = 9,3
[OH-] = 10^-9,3 M = 5,01*10^-10 M