Verified answer

iunno if this is rite.... but well..

1 = x√x

n x√x = x^3/2 so..

1 = x^3/2

therefore..

1 = x because watever u do to 1 its always gonna be 1

x= 1

1/(2x√x) = 1/2

2x√x = 2

x√x = 1

x^3 = 1

x^3 - 1 = 0

(x - 1) (x^2 + x + 1) = 0

x = 1 and x = (-1 +/- i√3)/2

1/(2x√x) = 1/2

2x√x = 2

x√x = 1

x^3 = 1

x^3 - 1 = 0

(x - 1) (x^2 +x+

1) = 0

x = 1 and x^2+x=-1

x^2=-(1+x)

i.e x={-(1+x)}^2

x=(1+x)^2

=> x^(1+1/2)=1

=> x^(3/2)=1

=>(x^(3/2=1)^(2/3)

=> x=1 (answer)

1=xtrx

1=x^(3/2)

1^2=x^3

3rdrt(1)=x

x=1

alternately

1/(2xrtx)=1/2

since you have identical numerators, the denominators must have equal values

2xrtx=2

x=1

well,pls refrain from asking simple questions or questions which you will be able to answer after a minute;s thinking.

anyways

the answer =1

if u want to know how, just x^(3/2) =1 ,so x =1

1/(2x√x) = 1/2

x√x=1

x^2*x=1

x^3=1

x=1

x3/2=1

x3=1

x=+/-1