Compute the following integral. 0 ∫ sqrt3 (4x/sqrt (x^2+9)) dx?
find the integral as it goes from 0 to the square root of 3 thanks
More Questions From This User See All
find the integral as it goes from 0 to the square root of 3 thanks
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
It helps if you recognise
d/dx[ln(x^2 + 9)] = [1/(x^2 + 9)]*2x
I = ∫ (4x/sqrt (x^2+9)) dx from 0 to sqrt3
I = 2 |ln(x^2 + 9)| from 0 to sqrt3
I = 2 |ln(x^2 + 9)| from 0 to sqrt3
I = 2 ln (4/3) ~ 0.57536
Regards - Ian