we asume that u=x^3+1
du=3x^2dx
we find
integral x^2 sqrt(x^3+1) dx = 2/9 (x^3+1)^(3/2)+constant
try this link below..
calculated from wolframalpha
http://www40.wolframalpha.com/input/?i=x2*square+r...
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Verified answer
we asume that u=x^3+1
du=3x^2dx
we find
integral x^2 sqrt(x^3+1) dx = 2/9 (x^3+1)^(3/2)+constant
try this link below..
calculated from wolframalpha
http://www40.wolframalpha.com/input/?i=x2*square+r...