A coffee-cup calorimeter contains 50.0 g of water at 60.51ºC. A 12.4 g piece of graphite at 24.21ºC is placed?
A coffee-cup calorimeter contains 50.0 g of water at 60.51ºC. A 12.4 g piece of graphite at
24.21ºC is placed in the calorimeter. The final temperature of the water and the carbon is
59.02ºC. Calculate the specific heat of carbon. The specific heat of water is 4.18 J/g·ºC.
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heat(J) = mass(g) x specific heat(J/g^C) x temp change(^C)
heat lost by water = heat gained by carbon
heat lost by water = 50 x 4.18 x (60.51 - 59.02) = 311.4J
311.4 = 12.4 x specific heat of carbon x (59.02 - 24.21)
specific heat of carbon = 0.721 J/g^C