By using the power formula in integration.
(A^N+1)/(N+1) +C
Then you'll get,
(15x^4+1)/(4+1)-(6x^2+1)/(2+1)+C
3x^5-2x^3+C
â«(15x^4-6x²+2)dx
=â«15x^4 dx-â«6x² dx+â«2dx
=(15/5)x^5-(6/3)x^3+2x+C
=3x^5-2x^3+2x+C
=3x^5 -2x^3 +2x +C
theres an integral symbol on the keyboard ahah?
3x^5-2x^3+2x+C
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Verified answer
By using the power formula in integration.
(A^N+1)/(N+1) +C
Then you'll get,
(15x^4+1)/(4+1)-(6x^2+1)/(2+1)+C
3x^5-2x^3+C
â«(15x^4-6x²+2)dx
=â«15x^4 dx-â«6x² dx+â«2dx
=(15/5)x^5-(6/3)x^3+2x+C
=3x^5-2x^3+2x+C
=3x^5 -2x^3 +2x +C
theres an integral symbol on the keyboard ahah?
3x^5-2x^3+2x+C