In general, ∫ x^n = (1/(n + 1))x^(n + 1) + C
So, ∫ (15x^4 - 6x² + 2) dx
= 15(1/(4 + 1))x^(4 + 1) - 6(1/(2 + 1))x^(2 + 1) + 2x
= 15(1/5)x^5 - 6(1/3)x³ + 2x + C
= 3x^5 - 2x³ + 2x + C
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In general, ∫ x^n = (1/(n + 1))x^(n + 1) + C
So, ∫ (15x^4 - 6x² + 2) dx
= 15(1/(4 + 1))x^(4 + 1) - 6(1/(2 + 1))x^(2 + 1) + 2x
= 15(1/5)x^5 - 6(1/3)x³ + 2x + C
= 3x^5 - 2x³ + 2x + C