Factors involving f=qvbsinθ affecting the size of the force on the particle?
Clarify the way in which each factor of the equation f=qvbsinθ affects the value of the force on the charged particle moving in the magnetic field.
I'm a bit unsure of this question, as I to my knowledge, if any factor increases, the force on the charged particle increases but I cannot find information to support this, and am unsure of how to show this relationship
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well i would say there is direct proportionality between the force and the charge, the velocity and the magnetic field. so the higher these are, the higher the resulting force will be. and the angle affects the force in the way that depending on the cirection of the movement relative to the magnetic field there will be a force between 0 and qvb. if the movement is parallel there will be no force, if it is perpendicular, the force will be qvb. for everything in between the force will develop in the "shape" of sine.
The fact, that the force is proportional to the charge q and the magnetic intensity, is natural to be understood (for instance, thinking of forces superposition). sinθ shows, that to get max. affection on the charge it should cross the magnetic lines perpendicularly. That is the basic of so-called magnetic lenses, as the charge inclines till it motion lays low on the magnetic intensity (than sinθ=0 and there is no inclining force).