S° (J/mol × K)
Zn(s) 60.9
HCl(aq) 56.5
H2(g) 130.58
Zn2+(aq) –106.5
Cl–(aq) 55.10
I got -38.2 J/K but I m not sure if that is correct.
∆S°rxn = sum of S° of products - sum of S° of reactants
∆S° = [-106.5 + 2(55.10) + 130.58] - [60.9 + 2(56.5)] = -39.6 J/K
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Answers & Comments
∆S°rxn = sum of S° of products - sum of S° of reactants
∆S° = [-106.5 + 2(55.10) + 130.58] - [60.9 + 2(56.5)] = -39.6 J/K