Given A + 1/2 (b+B)h, find the value of h if A= 12 cm squared, b=2 cm, and B= 4 cm?

Given A + 1/2 (b+B)h, find the value of h if A= 12 cm squared, b=2 cm, and B= 4 cm?

Given A + 1/2 (b+B)h, find the value of h if A= 12 cm squared, b=2 cm, and B= 4 cm?

Given A + 1/2 (b+B)h, find the value of h if A= 12 cm squared, b=2 cm, and B= 4 cm?

Given A + 1/2 (b+B)h, find the value of h if A= 12 cm squared, b=2 cm, and B= 4 cm?

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Presentation is incorrect.

Should be shown as :-

A = (1/2) ( b + B ) h

2 A / ( b + B ) = h = 24 / 6 = 4 cm

A = 1/2 (b + B)h, find the value of h

h = A/(1/2)(b + B) 

h = 12/(1/2)(2 + 4)

h = 4 cm (if A = 12 cm^2,  b = 2 cm, and B = 4 cm)

Did you mean A = (1/2) * (B + b) * h?

12 = (1/2) * (2 + 4) * h

It's not hard

12 = (1/2) * 6 * h

12 = 3h

12/3 = h

Can you finish it up?