please help i am having alot of trouble with this.
Assuming a quadratic equation.
4x^2 + 3 = - 12x
4x^2 + 3 + 12x = - 12x + 12x
4x^2 + 3 + 12x = 0
4x^2 + 12x + 3 = 0
Use the general formula
x = {- (+12) + Sqrt [ (+12)^2 - [4 X (+4) X (+3)]}/ 2 X (+4) or
x = {- (+12) - Sqrt [ (+12)^2 - [4 X (+4) X (+3)]}/ 2 X (+4)
x = (- 3 + Sqrt6)/2 or (- 3 - Sqrt6)/2
x = -0.27525512860841095090135796264705 or x = -2.7247448713915890490986420373529
x = - 0.28 (To the nearest hundredth) or x = - 2.72 (To the nearest hundredth)
What are the approximate solutions of 4x2 + 3 = −12x to the nearest hundredth?
x = [-12 + or - sqrt(144 - 48)]/8
x = ] -12 + or - 9.797959]/8
x = - 2.7247 or - 0.27525
rounded values of x = -2.72 or -0.28
------------------------------
4x^2 + 3 = −12x
4x^2 + 12 x + 3 = 0
this does not factor.
Quadratic formula
x = (-12 +- (144 - 4*4*3)^(1/2))/ 8
= (-12 +- sqrt 96) / 8
= -3/2 +- 1/2 sqrt 6
sqrt 6 ~ 2.45 -- is it actually a shade less
2.45/2 = 1.22
1.22 - 1.5 = -0.27
-1.22 - 1.5 = -2.72
x=0.15
Note that this is the exact answer
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Answers & Comments
Assuming a quadratic equation.
4x^2 + 3 = - 12x
4x^2 + 3 + 12x = - 12x + 12x
4x^2 + 3 + 12x = 0
4x^2 + 12x + 3 = 0
Use the general formula
x = {- (+12) + Sqrt [ (+12)^2 - [4 X (+4) X (+3)]}/ 2 X (+4) or
x = {- (+12) - Sqrt [ (+12)^2 - [4 X (+4) X (+3)]}/ 2 X (+4)
x = (- 3 + Sqrt6)/2 or (- 3 - Sqrt6)/2
x = -0.27525512860841095090135796264705 or x = -2.7247448713915890490986420373529
x = - 0.28 (To the nearest hundredth) or x = - 2.72 (To the nearest hundredth)
What are the approximate solutions of 4x2 + 3 = −12x to the nearest hundredth?
4x^2 + 12x + 3 = 0
x = [-12 + or - sqrt(144 - 48)]/8
x = ] -12 + or - 9.797959]/8
x = - 2.7247 or - 0.27525
rounded values of x = -2.72 or -0.28
------------------------------
4x^2 + 3 = −12x
4x^2 + 12 x + 3 = 0
this does not factor.
Quadratic formula
x = (-12 +- (144 - 4*4*3)^(1/2))/ 8
= (-12 +- sqrt 96) / 8
= -3/2 +- 1/2 sqrt 6
sqrt 6 ~ 2.45 -- is it actually a shade less
2.45/2 = 1.22
1.22 - 1.5 = -0.27
-1.22 - 1.5 = -2.72
x=0.15
Note that this is the exact answer