I have a triangle which I must find the area and it's base and height are 5 and 5√3. I then have 6 of these triangles total to find the area of a hexagon in exact value. I'm not sure how to multiply things with radicals to simplify it or keep it certain ways?
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
it is (5*5*6)*√3
= 150√3
edit: p.s. the area of a triangle is = (1/2) * base * height = (1/2) * 5 * 5√3
hence, total area would be (1/2)*5*5√3*6 = 75√3
25 sq rt 3 * 6= 150 sq rt 3
Area of a triangle is base times height divided by two.
In your case this is simply 25/2√3
you have six of the there total area is 150/2√3 which is 75√3 in exact number
so ig you deal with number and a radical simple multiply or divide the number without touching the radical.
If you have more than one radical then it is alot more complicated, propably beyond the scope of your assignment!
the only clarification why you have been waiting to sparkling up your final question (which became fixing for cos(a + b)) became because of the identity cos(a + b) = cos(a)cos(b) - sin(a)sin(b) for this reason there's a formula for sin(a + b) besides [refer on your textbook]: sin(a + b) = sin(a)cos(b) + sin(b)cos(a) Plugging on your proposed values, sin(a + b) = [4/5] [2/3] + [sqrt(5)/3][-3/5] sin(a + b) = [8/15] - sqrt(5)/5 To simplify all of it under one fraction, sin(a + b) = [8 - 3sqrt(5)]/5