Determine o vértice das funções?
a) f(x) = x² - 5x + 4
b) f(x) = -2x² + 3 = 1
c) f(x) = x² - 4
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a) f(x) = x² - 5x + 4
b) f(x) = -2x² + 3 = 1
c) f(x) = x² - 4
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Verified answer
f(x) = ax² + bx + c
Vértice
Vx = -b/2a
Vy = -delta²/4a
a) f(x) = x² - 5x + 4
Vx = -b/2a = - (-5)/2 = 5/2
delta² = (-5)² - 4*1*4 = 25 - 16 = 9
Vy = -delta²/4a = -9/4
b) f(x) = -2x² + 3 = 1
f(x) = -2x² + 2 = 0
Vx = -b/2a = -0/-4 = 0
delta² = 0² - 4(-2)*2 = 16
Vy = -delta²/4a = -16/-8 = 2
c) f(x) = x² - 4
Vx = -b/2a = -0/2 = 0
delta² = 0² - 4*(-4) = 16
Vy = -delta²/4a = -16/4 = -4
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