Verified answer

(2^n+3 + 2^n+2 - 2^n-1) / (2^n-2 + 2^n)

note que 2^n+3 = (2^n)(2^3) e 2^n+2 = (2^n).(2^2) e 2^n-1 = (2^n) .(2^-1) logo

2^n( (2^3 + (2^2) - 2^-1)/ 2^n ((2^-2) + 1) ------cancele 2^n

2^-1 = 1/2 e 2^-2 = 1/4

(8 + 4 -1/2)/ ((1/4) + 1) ====

(12 - 1/2)/ (1/4 +1)======mmc (2,1) = 2 e mmc (4,1) =4

(24/2 -1/2)(1/4 + 4/4) =(23/2)/(5/4) = (23/2)(4/5) = 46/5<<<<<<<<<

Observe atentamente!

Em caso de dúvida deixe recado!

Bons estudos, Manoel!

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(2^n+3 + 2^n+2 - 2^n-1) / (2^n-2 + 2^n)

(2^n.2³ + 2^n.2² - 2^n/2¹) / (2^n/2² + 2^n)

(8.2^n + 4.2^n - 2^n/2) / (2^n/4 + 2^n)

(12.2^n - 2^n/2) / (2^n/4 + 2^n)

(24.2^n/2 - 2^n/2) / (2^n/4 + 4.2^n/4)

(23.2^n/2) / (5.2^n/4)

(23.2^n/2) . (4/5.2^n)

92.2^n / 10.2^n

92/10

46/5 #

Ola Manoel

(8*2^n + 4*2^n - 2^n/2)/(2^n/4 + 2^n)

(8 + 4 - 1/2)/(1/4 + 1)

(64/8 + 32/8 - 4/8)/(2/8 + 8/8)

(64 + 32 - 4)/(2 + 8) = 92/10 = 46/5

pronto