A(g) + B(g) « C(g) + 2 D(g) Given one mole of A and one mole of B are placed in a 0.345-L container. After eq?
A(g) + B(g) « C(g) + 2 D(g)
Given one mole of A and one mole of B are placed in a 0.345-L container. After equilibrium has been established, 0.200 mole of C is present in the container. Calculate the equilibrium constant, Kc, for the reaction.
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Kc = [C][D]² / {[A][B]}
Kc = (0.200 mol / V)(2 * 0.200 mol / V)² / {[(1 - 0.200 mol) / V][(1 - 0.200 mol) / V]}
Kc = (0.200 mol / 0.345 L)(0.400 mol)² / (0.800 mol)²
Kc = 0.145 M