A 2.0cm × 2.0cm parallel-plate capacitor has a 2.0mm spacing. The electric field strength inside the capacitor is 1.4×10^5V/m .
What is the potential difference across the capacitor in volts?
How much charge is on each plate?
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Verified answer
p.d. across the capacitor is
V = E * d = 1.4*10^5 V/m * 2*10^-3 m = 280 V
charge on each plate is
Q = C*V = εo*A*V/d = εo*A*E assuming air dielectric
Q = 8.85*10^-12 * (2.0*10^-2)^2 * 1.4*10^5 = 4.96*10^-10 Coulomb