5(2y - 1) - (y - 12) + 2(3y - 5) =
10y - 5 - y + 12 + 6y - 10 =
15y - 3.
5(2y-1)-(y-12)+2(3y-5)
5(2y)-5(1)-y+12+2(3y)-2(5)
10y-5-y+12+6y-10
5y-5+12-10
5y+7-10
5y+(-3)
10y -5 -y + 12 +6y-10
=15y -3
= 3(5y-1)
10y-5-(y-12)+2(3y-5)
10y-5-y+12+6y-10 (- -12 is +12)
15y-3 (add like terms)
distribute!!
=15y-3
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Verified answer
5(2y - 1) - (y - 12) + 2(3y - 5) =
10y - 5 - y + 12 + 6y - 10 =
15y - 3.
5(2y-1)-(y-12)+2(3y-5)
5(2y)-5(1)-y+12+2(3y)-2(5)
10y-5-y+12+6y-10
5y-5+12-10
5y+7-10
5y+(-3)
10y -5 -y + 12 +6y-10
=15y -3
= 3(5y-1)
10y-5-(y-12)+2(3y-5)
10y-5-y+12+6y-10 (- -12 is +12)
15y-3 (add like terms)
distribute!!
10y-5-y+12+6y-10
=15y-3