x^3−x^2+x−6 if x equal -3 then it should be 27 why am i wrong
The correct answer will be -45.
(-3)^3 - (-3)^2 + (-3) - 6 = -27 - (9) - 3 - 6 = - 45
-27 - 9 - 3 - 6 = -45
x^3=(-3)^3=-27, sine -3*-3=9 and 9*-3=-27
x^2=9, since -3*-3=9
-27-9+(-3)-6=?
Are you sure the answer is 27?
-27-9=-36 and
-36+-3-6=-36-3-6=-39-6=-45
-3^3--3^2+-3-6
-3•-3•-3=-27
-3•-3=9
-27-9+-3-6
-27+-9+-3+-6
-45
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Verified answer
The correct answer will be -45.
(-3)^3 - (-3)^2 + (-3) - 6 = -27 - (9) - 3 - 6 = - 45
-27 - 9 - 3 - 6 = -45
x^3=(-3)^3=-27, sine -3*-3=9 and 9*-3=-27
x^2=9, since -3*-3=9
-27-9+(-3)-6=?
Are you sure the answer is 27?
-27-9=-36 and
-36+-3-6=-36-3-6=-39-6=-45
-3^3--3^2+-3-6
-3•-3•-3=-27
-3•-3=9
-27-9+-3-6
-27+-9+-3+-6
-45