Verified answer

x^2 – 8x + 8 = 0 => assuming

x^2 - 8x = -8

x^2 - 8x + 16 = 16 - 8

(x - 4)^2 = 8

x - 4 = ±√8

x = 2(2±√2)

X^2-8x+8

It's prime don't worry nothing can multiply to make 8 and add to make -8 so it's prime. If it was something like x^2-8x+12 -6 and -2 multiply to make 12 and add to make -8. example

X^2-8x+12

(x-6)(x-2) use foil to double check x^2-2x-6x+12

X^2-8x+12 correct.

use the quadratic equation formula

x=(-b±√(b^2-4ac))/2a

where a is the coefficient of the leading term, be of the second leading term according to the degree of the equecion and c is the constant.

so you have

x=(-(-8)±√((8)^2-4(1)(8)))/2(1)

it gives you

x=(8±√(64-32))/2

then simplify

x=(8±√(32))/2

sqrt=5.66

so

X1= (8+5.66)/2 and X2= (8-5.66)/2

X1= 6.83 and X2= 1.17

approximate values.

Using quadratic formula

x = [8+/-{sqrt((-8)^2 -4(1)(8)}]/2

x = [8+/-{sqrt((64 -32)}]/2

x = [8+sqrt(32)]/2

x = 4+2sqrt(2) and x = 4-2sqrt(2) ......................Ans

look up the quadratic equation on google and plug it into that it will come as a radical