The amount of heat absorbed by the ice as it warms to 0°C is _______.?
Given the following:
- specific heat capacity of ice = 2,000 J/kg-°C
- latent heat of fusion of water = 334,000 J/kg
- specific heat capacity of water = 4,000 J/kg-°C
A 1 kg block of ice is removed from a freezer where its temperature was –10°C. The amount of heat absorbed by the ice as it warms to 0°C is __________.
Please show your work.
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Use the equation,
Q=m.s.t(change in temp.)[m=mass of ice,s=specific heat capacity of ice]
=1.(2000).(10)
=20,000joule or 20 kJ.
we do not need latent heat of fusion of water or specific heat capacity of water as there is no change in state.(no change from solid ice to liquid water)
1st increase the temperature of ice to 0.
Q = m * Sp ht * ∆T = 1 * 2000 * 10 = 2000 J
This is the amount of heat absorbed by the ice as it warms to 0°C
2nd melt the ice.
Q = Hf * m = 334,000 * 1 = 334,000 J
2000 + 334,000 = 336,000 J
This is the amount of heat absorbed by the ice as it warms to 0°C and melts
°C