Given the following:
- specific heat capacity of ice = 2,000 J/kg-°C
- latent heat of fusion of water = 334,000 J/kg
- specific heat capacity of water = 4,000 J/kg-°C
A 1 kg block of ice is removed from a freezer where its temperature was –10°C. The amount of heat absorbed by the ice as it warms to 0°C is __________.
Please show your work.
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Verified answer
Q (heat) = Cp (specific heat) × mass × temp. change
Q = 2kJ/kg°C × 1kg × 10°C = 20kJ
There's three things I'd like to add to Born Yesterday's answer, Jane. First, He's had to assume the quantity of water you're talking about since you don't specify what that is.....so he calculated the joules per kg., and you don't specify whether it's water at 0 degrees Celsius or ice at 0 degrees. Since you're adding the heat of fusion of ice, I'm going to assume you're taking about water at 0 degrees.
If that's the case then you just have to do one additional calculation to Born Yesterday's answer. That would be:
334 Kj/C x 20 Kj/Kg = 6680 Kj If you then raise the temperature of the water at 0 degrees Celsius, you would multiply your answer x 4 Kj/kg.