Find the slope of the graph of the function at the given point. Use the derivative feature of a graphing utility to confirm your result.
Function g(t) = −3 cos t + 5
Point (π, 8)
g(t) = -3cos(t) + 5
g'(t) = -3(-sin(t)) + 0 = 3sin(t)
At the point (pi, 8), we have:
g'(t)
= g'(pi)
= 3sin(pi)
= 3(0)
= 0
Thus, the slope is zero.
To check:
First step: http://www.wolframalpha.com/input/?i=d%2Fdx+%28-3c...
Second step: http://www.wolframalpha.com/input/?i=3+sin%28x%29+...
I am not sure how to check directly, unfortunately.
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Answers & Comments
g(t) = -3cos(t) + 5
g'(t) = -3(-sin(t)) + 0 = 3sin(t)
At the point (pi, 8), we have:
g'(t)
= g'(pi)
= 3sin(pi)
= 3(0)
= 0
Thus, the slope is zero.
To check:
First step: http://www.wolframalpha.com/input/?i=d%2Fdx+%28-3c...
Second step: http://www.wolframalpha.com/input/?i=3+sin%28x%29+...
I am not sure how to check directly, unfortunately.