I didn't understand it
find X :
2x²+5=2
It's simple algebra. To the inverse operation from the left side to the right side. But if you want to do anything with x, keep by itself.
2x² + 5 = 2
1) Subtract 5 from 2:
2x² = -3
2) Divide 2 because its multiplying itself by x²
x² = -3 / 2
3) Do the square root of x because the inverse of x² is √x
x = √( - 3 / 2 )
You can keep x as √( - 3 / 2 ) or i√( 3 / 2 ) or 1.22474i
2x^2+5-2=0
2x^2+3=0
2x^2=0-3
2x^2=-3
divide both sides by 2
x^2=-3/2
then square root that
2x^2+5=2
x=+-[sqrt3/sqrt2]i = +-i*(sqrt6)/2
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Verified answer
It's simple algebra. To the inverse operation from the left side to the right side. But if you want to do anything with x, keep by itself.
2x² + 5 = 2
1) Subtract 5 from 2:
2x² = -3
2) Divide 2 because its multiplying itself by x²
x² = -3 / 2
3) Do the square root of x because the inverse of x² is √x
x = √( - 3 / 2 )
You can keep x as √( - 3 / 2 ) or i√( 3 / 2 ) or 1.22474i
2x^2+5-2=0
2x^2+3=0
2x^2=0-3
2x^2=-3
divide both sides by 2
x^2=-3/2
then square root that
2x^2+5=2
2x^2=-3
x^2=-3/2
x=+-[sqrt3/sqrt2]i = +-i*(sqrt6)/2