Verified answer

(x + 6)(x - 1)(x - 4) =(x^2 + 5x - 6)(x - 4) = x^3 + 5x^2 - 6x - 4x^2 - 20x + 24 =

x*3 + x^2 -26x + 24

One (of the infinite number of polynomials that could be developed -- having those 3 roots is:

[x-(-6)] (x -1) (x-4) = 0 You mult the left side out and you have your polynomial.

X^3 + x^2 - 26x + 24

You have the roots, simple put them into the quadratics equations and expand them out. Like this: (x+6)(x-1)(x-4)

See the resemblance?