Use Boyle’s law to find P1 given?
V1 = 3.7 × 10e5 (10 to the 5th power) mL
P2 = 118 mm Hg,
V2 = 2.8 × 10e3 (10 to the 3rd power) mL.
Answer in units of mm Hg
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V1 = 3.7 × 10e5 (10 to the 5th power) mL
P2 = 118 mm Hg,
V2 = 2.8 × 10e3 (10 to the 3rd power) mL.
Answer in units of mm Hg
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Verified answer
P1V1 = P2V2
(x) (3.7 × 10e5 mL) = (118 mm Hg) (2.8 × 10e3 mL)
solve for x
V1 * P1 = V2 * P2
3.7 * 10^5 * P1 = 2.8*10^3 * 118
P1 = 2.8*10^3 * 118 / 3.7 * 10^5
P1 = 0.89 mm Hg