If the dimension you give is the side length, then the area is that value squared
(1+√2)(1+√2) = 1 + 2√2 + 2 = 3+√2
Assuming that 1 + â2 is the dimension of one side,
Area =side^2= (1 + â2)^2= 1+2*1*â2+(â2)^2= 1+2â2+2
=3+2â2
Area of square= a x a where a is the side of the square...so ans will be 1plus 2 equals 3
if you mean a side
1+ sq rt 2
===========
1+2 sq rt 2+2
3+2 sq rt 2 area
<facepalm> Dimension of what? 1 side? The diagonal? What?
Use ur math book
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Verified answer
If the dimension you give is the side length, then the area is that value squared
(1+√2)(1+√2) = 1 + 2√2 + 2 = 3+√2
Assuming that 1 + â2 is the dimension of one side,
Area =side^2= (1 + â2)^2= 1+2*1*â2+(â2)^2= 1+2â2+2
=3+2â2
Area of square= a x a where a is the side of the square...so ans will be 1plus 2 equals 3
if you mean a side
1+ sq rt 2
1+ sq rt 2
===========
1+2 sq rt 2+2
3+2 sq rt 2 area
<facepalm> Dimension of what? 1 side? The diagonal? What?
Use ur math book