In the reaction below the iron undergoes the first stage in the corrosion process. What is E° for a cell that employs this reaction?
Fe + 2 Ag+> --> Fe2+ + 2 Ag
a. 1.24 V
b. 0.36 V
c. - 1.24 V
d. 0.80 V
e. - 0.44 V
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Verified answer
If i remember correctly, reduction - oxidation = E cell Fe undergoes oxidation and Ag undergoes reduction.
-0.44 - 0.8 = -1.24
so I think it is C.
I hope this is what you were after.