I think you mean the substitution t = 7sinx
then dt = 7cosx dx, and dx = dt / 7cosx
you can plug in for x and dx
∫[49-(7sinx)^2]^(1/2) dt/7cosx
simplify the expression inside the brackets
[49 - 49sin^2(x)]^(1/2) = [49(1-sin^2(x)]^(1/2) = 7sqrt(1-sin^2(x))
use the identity cos^2(x)+sin^2(x) = 1, so sqrt(1-sin^2(x)) = cos(x)
term in brackets = 7cosx
∫7cosx * dt/7cosx = ∫dt = t + C = 7sinx + C
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Verified answer
I think you mean the substitution t = 7sinx
then dt = 7cosx dx, and dx = dt / 7cosx
you can plug in for x and dx
∫[49-(7sinx)^2]^(1/2) dt/7cosx
simplify the expression inside the brackets
[49 - 49sin^2(x)]^(1/2) = [49(1-sin^2(x)]^(1/2) = 7sqrt(1-sin^2(x))
use the identity cos^2(x)+sin^2(x) = 1, so sqrt(1-sin^2(x)) = cos(x)
term in brackets = 7cosx
∫7cosx * dt/7cosx = ∫dt = t + C = 7sinx + C