Solve
4/3πr^3 = 15 in^3
r^3 = 45/4π
Real solution:
r ≈ 1.5299 in
Assuming that have to find r
V = (4/3) π r³
[ 3V / 4π ] = r³
[ 3V / 4π ]^(1/3) = r
I'll guess that you want to find the value of r that makes V=15 in³.
If so, my approach is always to solve in symbols (where possible) to avoid errors writing out long intermediate results. So
V = (4/3) π r³ . . . . given
3V = 4π r³ . . . . multiply by 3 to clear fractions
(3V)/(4π) = r³ . . . . divide by 4π to isolate r
r = ∛[ (3V) / (4π) ] . . . . turn around and take cube roots
Now you're set to find the radius of any sphere, given its volume. For V=15 that's ∛[45 / (4π)]
or about 1.19366 ft. Just over 14 5/16 inches.
If your calculator doesn't have a cube root function, use a 1/3 power instead:
r = [ (3V) / (4π) ] ^ (1/3)
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Answers & Comments
4/3πr^3 = 15 in^3
r^3 = 45/4π
Real solution:
r ≈ 1.5299 in
Assuming that have to find r
V = (4/3) π r³
[ 3V / 4π ] = r³
[ 3V / 4π ]^(1/3) = r
I'll guess that you want to find the value of r that makes V=15 in³.
If so, my approach is always to solve in symbols (where possible) to avoid errors writing out long intermediate results. So
V = (4/3) π r³ . . . . given
3V = 4π r³ . . . . multiply by 3 to clear fractions
(3V)/(4π) = r³ . . . . divide by 4π to isolate r
r = ∛[ (3V) / (4π) ] . . . . turn around and take cube roots
Now you're set to find the radius of any sphere, given its volume. For V=15 that's ∛[45 / (4π)]
or about 1.19366 ft. Just over 14 5/16 inches.
If your calculator doesn't have a cube root function, use a 1/3 power instead:
r = [ (3V) / (4π) ] ^ (1/3)