Algebraically determine the solution to this equation
cos(½x) = -(√3)/2
cos(x/2) = -√3/2
x/2 = 5PI/6
x=10PI/6
The period of cos(x/2) = 2PI/(1/2) = 4PI
The general solution is : x = 10PI/6+4nPI, where n is any integer
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cos(x/2) = -√3/2
x/2 = 5PI/6
x=10PI/6
The period of cos(x/2) = 2PI/(1/2) = 4PI
The general solution is : x = 10PI/6+4nPI, where n is any integer