The radius of the Earth is about 6.37 × 10^6 m. a) What is the centripetal acceleration of a point on the equa?
The radius of the Earth is about 6.37 × 10^6 m. a) What is the centripetal acceleration of a point on the equator due to the rotation of earth about its axis.
Answer in units of m/s^2.
b) What is the centripetal acceleration of a point at the North Pole? Answer in units of m/s^2.
More Questions From This User See All
Answers & Comments
Verified answer
The period of rotation is 1 day, or
T = 24hr * 3600s/hr = 86 400 s
Then ω = 2π/T = 7.27e-5 rad/s
centripetal a = ω² r = 0.034 m/s²
(about a third of a percent of gravity)
At the north pole, the centripetal acceleration is zero since the radius of revolution is zero.