You can use FOIL here. I won't explain it because that would take too long to type, but I'll include a link in the source (although you should just check your book).
√(5)*√(5) + √(5)*2 + (-2)*√(5) + (-2)*(2)
Simplify it now
5 + √(5)*2 - (2)*√(5) - 4 <------ Notice how the signs were used here. Always watch out for the negatives.
We can see that there's a positive √(5)*2 and then a negative √(5)*2, so those cancel.
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Verified answer
You can use FOIL here. I won't explain it because that would take too long to type, but I'll include a link in the source (although you should just check your book).
√(5)*√(5) + √(5)*2 + (-2)*√(5) + (-2)*(2)
Simplify it now
5 + √(5)*2 - (2)*√(5) - 4 <------ Notice how the signs were used here. Always watch out for the negatives.
We can see that there's a positive √(5)*2 and then a negative √(5)*2, so those cancel.
Leaving us with 5 - 4, which = 1. :D
Identity Used : (a - b)(a + b) = (a² - b²)
Hence,
(â5-2)(â5+2) = { (â5)² - (2)² } = (5 - 4) = 1
a sum times the difference of the same two numbers is always the difference of the two squares
5 - 4 = 1
foil it
5+ 2root5 - 2root5 - 4
5-4
1
1.