The radius of the Earth is about 6.37 × 106 m.
a) What is the centripetal acceleration of a
point on the equator?
Answer in units of m/s2
b) What is the centripetal acceleration of a
point at the North Pole?
Answer in units of m/s2
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Verified answer
a) Assuming the earth is a sphere, the circumference is 2*π*r = 2*( 3.1416 )*6.37*10^6 = 40.0*10^6 m
Since it rotates a complete circle once every 24 hours, the rim velocity is:
v = 40.0*10^6/(24*60*60) = 463.2 m/s
The centripetal acceleration is:
a = v^2/r = 463.2^2/6.37*10^6 = .0337 m/s^2
b) At the North Pole, the rim velocity would be zero, since the axis of rotation passes through the North Pole, so the centripetal acceleration would also be zero.