If a sample of C−14 initially contains 1.4
mmol of C−14, how many millimoles will be left after 2240 years?
_________ mmol
No. of half-lives = 2240/5730
C-14 left after 2240 years = (1.4 mmol) × (1/2)^(2240/5730) = 1.07 mmol
.547
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Answers & Comments
No. of half-lives = 2240/5730
C-14 left after 2240 years = (1.4 mmol) × (1/2)^(2240/5730) = 1.07 mmol
.547