Hint:
tan θ = -2.662 and cos θ > 0
so
θ in the 4th quadrant
tan T = -2.662
cos T > 0 so T lies in quadrant IV
T = arctan(-2.662) =-1.21145
The angle in the fourth quadrant is 2pi-1.21145 = 5.0717 radian (290.59 degrees)
290.589° = 5.072 radians
arctan ( - 2.662 ) + 2π
cosθ > 0 ⇒ θ is in Quadrant I or IV
tanθ < 0 ⇒ θ is in Quadrant II or IV
∴ θ is in Quadrant IV
θ = arctan(-2.662) ≅ 290.6°
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Answers & Comments
Hint:
tan θ = -2.662 and cos θ > 0
so
θ in the 4th quadrant
tan T = -2.662
cos T > 0 so T lies in quadrant IV
T = arctan(-2.662) =-1.21145
The angle in the fourth quadrant is 2pi-1.21145 = 5.0717 radian (290.59 degrees)
290.589° = 5.072 radians
arctan ( - 2.662 ) + 2π
cosθ > 0 ⇒ θ is in Quadrant I or IV
tanθ < 0 ⇒ θ is in Quadrant II or IV
∴ θ is in Quadrant IV
θ = arctan(-2.662) ≅ 290.6°